Coding Challenge Practice - Question 68

The provided code defines a function to check if a given number is prime. Numbers less than or equal to 1 are immediately identified as not prime. The number 2 is explicitly defined as prime. Even numbers greater than 2 are not prime. The code then calculates the square root of the input number as a limit for checking divisibility. A loop iterates through odd numbers from 3 up to this limit. If the input number is divisible by any number in this range, it is deemed not prime. If no divisors are found, the function concludes that the number is prime. The function efficiently determines primality by checking divisibility only up to the square root. The function returns `true` if the number is prime and `false` otherwise.